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1/a(a+1)+1/(a+1)(a+2)+1/(a+2)(a+3 )+……+1/(a+2009)(a+2010)
人气:227 ℃ 时间:2020-04-23 07:55:44
解答
1/a(a+1)+1/(a+1)(a+2)+1/(a+2)(a+3 )+……+1/(a+2009)(a+2010)=1/a-1/(a+1)+1/(a+1)-1/(a+2)+1/(a+2)-1/(a+3 )+……+1/(a+2009)-1/(a+2010)=1/a-1/(a+2010)=2010/[a(a+2010)]
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