1) f(π/3)=根号2cos(π/4)=1
2) θ第4象限 sinθ=-4/5
f(θ-π/6)=根号2cos(θ-π/2)=根号2sinθ=-4根号2/5需要具体求解过程1) f(π/3)=根号2cos(π/3-π/12)=根号2cos(π/4)=12)θ第4象限cosθ=3/5sinθ= -4/5 f(θ-π/6)=根号2cos(θ-π/2)=根号2sinθ=-4根号2/5过程就这么点吗？本来就这样简单