> 数学 >
y=sinxcosx+根号3cos^2 x,单调递增区间
人气:359 ℃ 时间:2020-06-18 00:41:22
解答
sinxcosx=1/2sin2x,则y=sinxcosx+根号3cos^2 x
=1/2sin2x+根号3cos^2 x
=sin(2x+π/3)
2kπ-π/2
推荐
猜你喜欢
© 2024 79432.Com All Rights Reserved.
电脑版|手机版