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a=根号下 7-1.求:3a 立方+12a平方-6a-12
人气:118 ℃ 时间:2019-11-25 21:38:11
解答
a+1=根号下7
(a+1)^2=7
a^2+2a=6
3a^3+12a^2-6a-12
=3a^3+6a^2+6a^2-6a-12
=3a(a^2+2a)+6a^2-6a-12
=3a*6+6a^2-6a-12
=6a^2+12a-12
=6(a^2+2a)-12
=6*6-12
=24
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