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(1-sinx)/cosx 化简成tanx/2的式子
人气:154 ℃ 时间:2020-05-19 05:33:25
解答
(1-sinx)/cosx=[sin²(x/2)+cos²(x/2)-2sin(x/2)cos(x/2)]/[cos²(x/2)-sin²(x/2)]=[cos(x/2)-sin(x/2)]²/{[cos(x/2)+sin(x/2)]*[cos(x/2)-sin(x/2)]}=[cos(x/2)-sin(x/2)]/[cos(x/2)+sin(x...
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