解方程3x^2+9x+10=64
4x^2+2x-1=0
3x(x-5)=4x-20
人气:164 ℃ 时间:2020-04-10 05:46:45
解答
3x^2+9x+10=643x^2+9x-54=0x^2+3x-18=0(x+6)(x-3)=0x=-6或x=3 4x^2+2x-1=0(2x)^2+2x+1/4=5/4(2x+1/2)^2=5/42x+1/2=±√5/2x=(√5-1)/4或x=(-1-√5)/43x(x-5)=4x-203x^2-19x+20=0(x-5)(3x-4)=0x=5或x=4/3...
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