化简：1/(x+1)-(x-3)/(x2-1)×(x2-2x+1)/(x2+4x+3)——题目没有出错,能者快来,_数学解答

化简：1/(x+1)-(x-3)/(x2-1)×(x2-2x+1)/(x2+4x+3)——题目没有出错,能者快来,

人气：287 ℃　时间：2020-05-11 04:52:42

解答

原式
=1/(x+1)-[(x-3)(x-1)(x-1)]/[(x+1)(x-1)(x+1)(x+3)]
=1/(x+1)-[(x-3)(x-1)]/[(x+1)(x+1)(x+3)]
=1/(x+1)×{1-[(x-3)(x-1)]/[(x+1)(x+3)]}
=1/(x+1)×{8x/[(x+1)(x+3)]}
=8x/[(x+1)(x+1)(x+3)]