tanA=1/2,tanB=1/3tanC=tan[180°-(A+B)] = -tan(A+B) = -(tanA+tanB)/(1-tanAtanB) = -(1/2+1/3)/(1-1/2*1/3) = -1C=135°C为最大角,所对的边c为最长边tanA＞tanBB为最小角,最短边c=1sinB=tanB/√(1+tan^2B)=(1/3)/...