an是等比数列,a1a2a3=1,a4a5a6=-2,求公比
不知道题目对不对可能是a1+a2+a3=1,a4+a5+a6=-2如果两种都能算的话就都算吧
人气:135 ℃ 时间:2020-09-08 09:22:47
解答
a1a2a3=1,a4a5a6=-2a2、a5为等比中项所以a2^3=1 a2=1a5^3=-2 a5=-³√2所以q=³√(a5/a2)a1+a2+a3=1,a4+a5+a6=-2a1+a2+a3=1,a1+a1*q+a1q^2=1,a1*(1+q+q^2)=1a4+a5+a6=-2,a1*q^3+a1*q^4+a1*q^5=-2,q^3*a1*(...
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