一道数学题:1/x-1+1/(x-1)(x-2)+1/(x-2)(x-3)+.+1/(x-99)(x-100)
人气:447 ℃ 时间:2019-08-18 18:30:05
解答
原式=1/(x-1)+[1/(x-2)-1/(x-1)]+[1/(x-3)-1/(x-2)]……+[1/(x-100)-1/(x-99)]
=1/(x-1)-1/(x-1)+1/(x-2)-1/(x-2)+……+1/(x-99)-1/(x-99)+1/(x-100)
=0+0+……+1/(x-100)
=1/(x-100)
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