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复数计算 (1-根号3i)^10-(1+根号3i)^10=?
人气:101 ℃ 时间:2020-03-25 01:32:02
解答
解析:(1-根号3i)^10=2^10 ×(1/2 -根号3/2 ×i)^10=2^10 ×[cos(-π/3)+sin(-π/3)×i]^10=2^10 ×[cos(-10π/3)+sin(-10π/3)×i]=2^10 ×[cos(2π/3)+sin(2π/3)×i]=2^10 ×(-1/2+根号3/2×i )而 (1+根号3i)^1...
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