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已知tana=-1/3求sin²a+3sinacosa-1的值
人气:310 ℃ 时间:2020-04-14 20:36:25
解答
tana=-1/3sina/cosa=-1/3-3sina=cosacos²a+sin²a=19sin²a+sin²a=110sin²a=1sin²a=1/10sin²a+3sinacosa-1=sin²a-9sin²a-1=-8sin²a-1=-8/10-1=-9/5
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