> 数学 >
(x+y-5)的绝对值+(xy-6)^2=0,求x^2+y^2
人气:119 ℃ 时间:2020-06-04 00:56:51
解答
(x+y-5)的绝对值+(xy-6)^2=0,
x+y-5=0
xy-6=0
x+y=5 xy=6
x²+y²
=x²+2xy+y²-2xy
=(x+y)²-2xy
=25-6×2
=13
推荐
猜你喜欢
© 2024 79432.Com All Rights Reserved.
电脑版|手机版