bsinA=asinBasinAsinB+bcos²A=√2absin²a+bcos²A=√2ab=√2ab/a=√2(2)b²=2a²c²=b²+√3a²=2a²+√3a²c=a√[2+√3] =a√[(4+2√3)/2] =a(√3+1)/√2余弦定理co...