设f(x)=sinx^2+sin2x-2cosx^2,此题实际上就是求f(x)的值域,具体解答如下:f(x)=sinx^2+sin2x-2cosx^2=(sinx^2+cosx^2)+sin2x-3cosx^2=1+sin2x-3(1+cos2x)/2=sin2x-3/2*cos2x-1/2=√13/2*sin(2x-y)-1/2所以f(x)的值域...