求由方程sin(x+y)=cosxlny所解定的隐函数的导数dy/dx
人气:398 ℃ 时间:2020-02-05 14:41:26
解答
sin(x + y) = cosx lnydsin(x + y)/d(x + y) · d(x + y)/dx = lny d(cosx)/dx + cosx d(lny)/dy · dy/dxcos(x + y) · (1 + dy/dx) = lny · (- sinx) + cosx · 1/y · dy/dxcos(x + y) + cos(x + y) dy/dx = - s...
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