答：过点A(-3,2)的直线设为：y-2=k(x+3)kx-y+3k+2=0原点到直线的距离：d=|0-0+3k+2| /√(k²+1²)=3|3k+2|=3√(k²+1)两边平方：9k²+12k+4=9k²+912k=5k=5/12直线为：(5/12)x-y+5/4+2=05x-12y+...