a1=2,a(n+1)=2an,写出数列前5项,猜想an并证明
a1=2
a2=4
a3=8
a4=16
a5=32
如何证明?an=2的n次方
人气:498 ℃ 时间:2020-05-20 05:11:02
解答
根据
a(n+1)÷an=2
所以
an=2a(n-1)=2²a(n-2)=……=2的n次方
an=2的n次方
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