已知x+y=派/4,求(1+tanx)(1+tany) 已知sin(派/4+x)*sin(派/4-x)=1/6,且x属于(2派,派),求sin4x的值
人气:393 ℃ 时间:2020-10-01 23:33:45
解答
x+y=π/4,
tanx+tany=1-tanxtany,
(1+tanx)(1+tany)
=1+(tanx+tany)+tanxtany
=2.
积化和差公式
sin(π/4+x)*sin(π/4-x)
=-1/2[cos π/2-cos2x]
=1/6.
cos2x=1/3>0,
又x∈(-2π,π),
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