已知x+y=派/4,求(1+tanx)(1+tany) 已知sin(派/4+x)*sin(派/4-x)=1/6,且x属于(2派,派),求sin4x的值
人气:341 ℃ 时间:2020-10-01 23:33:45
解答
x+y=π/4,
tanx+tany=1-tanxtany,
(1+tanx)(1+tany)
=1+(tanx+tany)+tanxtany
=2.
积化和差公式
sin(π/4+x)*sin(π/4-x)
=-1/2[cos π/2-cos2x]
=1/6.
cos2x=1/3>0,
又x∈(-2π,π),
推荐
- 已知sin(x+y)=1/2,sin(x-y)=1/3,求tanx,tany
- 实数x,y满足tanx=x,tany=y,且|x|≠|y|,则sin(x+y)x+y−sin(x−y)x−y=_.
- 已知sin(X+Y)=2/3,sin(X-Y)=1/5,求(tanX)/(tanY)的值
- 证明 (tanX+tanY)/(tanX-tanY)=(sin(X+Y))/(sin(X-Y))
- 已知a=(1,sin^2(x)),b=(2,sin2x),其中x属于(0,派),若|向量a·向量b|=|向量a||向量b|,则tanx的值为
- 【数学方程】50%×(1-1/5)=(1-1/4x)怎么解
- (2+1)(2²+1)(2∧4+1)(2∧6+1)…(2∧32+1)+1 (2∧16表示2的16次方)
- what makes one person more intelligent
猜你喜欢