f(x+y)=f(x)+f(y)+2xy
人气:338 ℃ 时间:2020-05-09 20:54:17
解答
游客1:定义在R上的函数f(x)满足f(x+y)=f(x)+f(y)+2xy(x,y∈R)f(1)=2,
则f(-3)=?
2:设f(x)是连续偶函数,且当x>0时f(x)是单调函数,则满足f(x)=f(x+3/x+4)的所有x之和为?
3:函数f(x)满足:⑴定义域是(0,+∞)⑵当x>1时,f(x)<2;⑶对任意x,y∈(0,∞)总有f(xy)=f(x)+f(y)-2.求:1,f(1)的值.2,判断函数f(x)的单调性,并用定义予以证明.
4:已知函数f(x)在(-1,1)上有意义,f(1/2)=-1,当且仅当时5:已知函数f(x)=1/a -1/x (a>0,x>0),若f(x)在区间[m,n]上的值域仍为[m,n],求a的取值范围.
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