无解啊!sin(√3-1)x × sin(√3+1)x=sin〔√3x-x〕×sin〔√3x+x〕=-1/2〔 cos 2√3x -cos2x〕=-1/2[〔 1-2sin^2(√3x) )- (1- 2sin^2(x) )]=sin^2(x) - sin^2(√3x) = 10≤sin^2(x)≤1 0≤ sin^2(√3x)≤1 你看还有...