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若函数f(x)的解析式为f(x)=2tanx-(2sin^2 (x/2) -1)/(sinx/2*cosx/2)
30 - 解决时间:2007-11-3 12:34
1.若函数f(x)的解析式为f(x)=2tanx-(2sin^2 (x/2) -1)/(sinx/2*cosx/2)
则f(π/12)是
2.已知α为锐角,且sinα=4/5 (1)求sin^2+sin2α/cos^2 α +cos2α的值(答案20)
(2)tan(α-5π/4) (答案1/7)
人气:415 ℃ 时间:2019-10-23 06:30:00
解答
1)f(x)=2tanx-(2sin^2 (x/2) -1)/(sinx/2*cosx/2) f(x)=2tanx +cos x /(1/2 * sin x ) =2tanx +2 cotx =2[(sin x /cos x )+(cos x /sin x)]=4/sin(2x) 将π/12带入,=8 1)求sin^2+sin2α/cos^2 α +cos2α sinα=4/...
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