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用换元法分解因式(x^2+4x+3)(x^2+12x+35)+15
人气:300 ℃ 时间:2020-04-18 11:18:02
解答
(x^2+4x+3)(x^2+12x+35)+15
=(x+1)(x+3)(x+5)(x+7)+15
=(x^2+8x+7)(x^2+8x+15)+15
设t=x^2+8x+11,
上式=(t-4)(t+4)+15
=t^2-16+15
=(t-1)(t+1)
=(x^2+8x+10)(x^2+8x+12)
=(x+4+√6)(x+4-√6)(x+2)(x+6).
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