函数f(x)=sin2x-cos2x,怎么化简到f(x)=√2sin(2x-π/4)的.._数学解答

函数f(x)=sin2x-cos2x,怎么化简到f(x)=√2sin(2x-π/4)的..

人气：379 ℃　时间：2019-09-01 10:58:45

解答

f(x)=sin2x-cos2x
=√2*[sin2x*(√2)/2 - cos2x*(√2)/2]
=√2*[sin2x*cos(π/4) -cos2x*sin(π/4)]
=√2*sin(2x-π/4)