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计算1、(2/3ab²-ab+3/4b)(-1/2ab) 2、(x+2y-3/2)(x-2y+3/2)
人气:107 ℃ 时间:2020-02-02 23:11:29
解答
1,=-1/3a^2b^3+1/2a^2b^2-3/8ab^2
2,=[x+(2y-3/2)][x-(2y-3/2)]
=x^2-(2y-3/2)^2
=x^2-4y^2+6y-9/4
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