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已知x的2次方+2x-y+6y-8=0,且x+y≠2,求x-y的值
人气:415 ℃ 时间:2019-08-26 07:26:03
解答
x²+2x-y²+6y-8
=(x²+2x+1)-(y²-6y+9)
=(x+1)²-(y-3)²=0
(x+1+y-3)(x+1-y+3)=0
(x+y-2)(x-y+4)=0
x+y≠2,x+y-2≠0
x-y+4=0
x-y=-4
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