对下列题目进行因式分解:1.(x+1)*(x+2)*(x+3)*(x+4)-120 2.(x-1)*(x-3)*(x+1)*(x+3)-20
括号之间的是乘号
用拆项添项法
求求求
人气:247 ℃ 时间:2020-05-08 19:28:41
解答
1.(x+1)*(x+2)*(x+3)*(x+4)-120 =(x+1)(x+4)(x+2)(x+3)-120=(x^2+5x+4)(x^2+5x+6)-120设t=x^2+5x则原式=(t+4)(t+6)-120=t^2+10t+24-120=t^2+10t-96(十字相乘)=(t+16)(t-6)=(x^2+5x+16)(x^2+5x-6)=(x^2+5x...
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