解由y=sin(3x+π/3)cos(x-π/6)-cos(3x+π/3)sin(x-π/6)
=sin[(3x+π/3)-(x-π/6)]
=sin(2x+π/2)
=cos2x
令2x=kπ,k属于Z
故函数的对称轴方程x=kπ/2,k属于Z
故函数的一条对称轴方程为x=0.