圆x^2+y^2+2x+4y-3=0(x+1)^2+(y+2)^2=8设x=-1+2√2cosay=-2+2√2sina到直线x+y+1=0的距离d=|-2+2√2cosa+2√2sina|/√2=|4sin(a+π/4)-2|/√2=√24sin(a+π/4)-2=2或 4sin(a+π/4)-2=-2sin(a+π/4)=1 或 4sin(a+π/4...