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设f=[sin(2/x)]=1+cosx,求f(x),f[cos(2/x)].
如题!
人气:114 ℃ 时间:2020-05-03 04:50:14
解答
cosx=1-2(sinx/2)^2
f=[sin(2/x)]=1+cosx=2-2(sinx/2)^2
f(x)=2-2x^2
f[cos(2/x)]=2-2[cos(2/x)]^2
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