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数学(2x+1/x^2)^n的展开式中,第三项的二项式系数比第二项的二项式系数大27,求展开式中的常数项
人气:116 ℃ 时间:2020-03-22 15:57:19
解答
C(2,n) - C(1,n) = 27
n(n-1)/(1*2) - n = 27
n(n-1) - 2n = 54
n(n-3) = 54 = 9×6
n = 9
(2x+1/x²)^n展开式中的常数项
= C(3,9) × (2x)^6 × (1/x²)³
= C(3,9) × 2^6 × x^6 × (1/x^6)
= C(3,9) × 2^6
= (9×8×7) / (1×2×3) × 2^6
= 3×4×7 × 2^6
= 3×7 × 2^8
= 21 × 256
= 5376
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