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limsin(3x-4)/9x^2-16
求极限为多少.
人气:320 ℃ 时间:2020-10-01 04:08:54
解答
limsin(3x-4)/9x^2-16=limsin(3x-4)/(3x-4)(3x+4)=limsint/t(t+8),t=3x+4
=limsint/t*lim1/(t+8),t=3x+8
=1×1/8=1/8
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