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cosθ^2+cos(θ+2π/3)^2+cos(θ-2π/3)^2 计算
人气:469 ℃ 时间:2020-09-30 18:02:54
解答
cos^2θ+cos^2(θ+2π/3)+cos^2(θ-2π/3)=(1+cos2θ)/2+[1+cos(2θ+4π/3)]/2+[1+cos(2θ-4π/3)]/2=3/2 +[cos2θ+cos(2θ+4π/3)+cos(2θ-4π/3)]/2cos2θ+cos(2θ+4π/3)+cos(2θ-4π/3)=cos2θ+cos2θcos(4π/3)...
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