√[(a+1/a)²-4]-√[(a-1/a)²+4]=√(a²+2+1/a²-4)-√(a²-2+1/a²+4)=√(a-1/a)²-√（a+1/a)²=│a-1/a│-│a+1/a│∵-1＜a＜0,∴a+1/a＜0,a＞1/a∴原式=a-1/a+a+1/a=2a明教为...