1、设(x²+1)/(x+1)=y∴原方程可化为y+3/y=4y²-4y+3=0(y-1)(y-3)=0∴y=1 y=3∴(x²+1)/(x+1)=1 (x²+1)/(x+1)=3x²+1=x+1 x²+1=3x+3x²-x=0 x²-3x-2=0x=1 x=0 x=(3+√17)/2 x=(3...