sinx的5次方的积分怎么求?
人气:454 ℃ 时间:2020-02-06 04:53:23
解答
(sinx)^5 = (sinx)^4 * sinx = (1-(cosx)^2)^2* sinx = (1 - 2(cosx)^2 + (cosx)^4)* sinx ∫ (1 - 2(cosx)^2 + (cosx)^4)* sinx * dx= - ∫ (1 - 2(cosx)^2 + (cosx)^4)* dcosx= - [ cosx - 2/3 (cosx)^3 + 1/5 (co...
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