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x4+y4+z4-2x2y2-2y2z2-2z2x2
人气:405 ℃ 时间:2020-10-01 19:10:08
解答
原式=x4-2x2y2+y4-2y2z2-2z2x2+z4=(x2-y2)2-2z2(x2+y2)+z4=(x2-y2)2-2z2(x2-y2)+z4-4x2y2=(x2-y2-z2)2-4x2y2=(x2-y2-z2-2yz)(x2-y2-z2+2yz)=[x2-(y+z)2][x2-(y-z)2]=(x+y+z)(x-y-z)(x+y-z)...
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