f(x)=cos(x+π/4+x-π/4)+tsin2x=cos2x+tsin2x
1.t=2时,f(x)=cos2x+2sin2x=√5sin(2x+arctan0.5)
在x∈[0,π/2]上,f(x)最大值为√5
f(x)最小值为√5sin(2*π/2+arctan0.5)=-1
2.f(x)=√(t^2+1)sin(2x+arctan(1/t))
f(x)在x∈[π/12,π/6]上为增函数
-π/2