x1 + x2 + x3 + x4 + x5 = 7 4x1 + 2x2 + 3x3 + 2x4 - 2x5 = 5 x1 + 3_数学解答

x1 + x2 + x3 + x4 + x5 = 7 4x1 + 2x2 + 3x3 + 2x4 - 2x5 = 5 x1 + 3x2 + 2x3 + 3x4 + 7x5 = 30
求这方程组的通解并指出它的一个特解
x1 + x2 + x3 + x4 + x5 = 7
4x1 + 2x2 + 3x3 + 2x4 - 2x5 = 5
x1 + 3x2 + 2x3 + 3x4 + 7x5 = 30

人气：268 ℃　时间：2020-01-27 08:40:23

解答

化简是正确的
x3 = c1,x4 =c2,x5 = c3
代入计算x1,x2用 c1,c2,c3表示
就得到了通解
{-(9/2),23/2,0,0,0}