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已知方程1/4+5(x-1/2009)=1/2,求式子3+20(x-1/2009)的值.
人气:122 ℃ 时间:2019-10-11 16:08:57
解答
1/4+5(x-1/2009)=1/2
5(x-1/2009)=1/2-1/4
5(x-1/2009)=1/4
4*5(x-1/2009)=4*1/4
20(x-1/2009)=1
3+20(x-1/2009)
=3+1
=4
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