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数学
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a=2,b=-4,c=-2,且x=-b+根号下(b^2-4ac)的和/2a,求x的值
人气:286 ℃ 时间:2020-06-19 00:36:19
解答
b^2=16 -4ac=-4*2*(-2)=16
x=-b+根号下(b^2-4ac)的和/2a
=[4+√(16+16)]/4
=(4+4√2)/4
=1+√2
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