解下列方程：2/x-1-3/x+1=x+3/x²-1;6x-2/2x-1-6x-3/3x-1=1.
最好有详细计算过程
人气：241 ℃ 时间：2020-02-20 21:39:34
解答
2/(x-1)-3/(x+1)=(x+3)/(x²-1)2(x+1)/(x-1)(x+1)-3(x-1)/(x+1)(x-1)=(x+3)/(x²-1)(2x+2)/(x²-1)-(3x-3)/(x²-1)=(x+3)/(x²-1)(2x+2)/(x²-1)-(3x-3)/(x²-1)-(x+3)/(x²-1)=0(2...
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