依题意得:：把等式两边同时乘以2,得2m²+2n²+2mn+2m -2 n+2=0∴(m²+n²+2mn)+（m²+2m+1)+（n² - 2n+1）=0∴(m+n)²+(m+1)²+(n - 1)²=0∴m+1=0 n - 1=0∴m= -1 n=1∴m/100...