求数列1/3,2/9,3/27,···,n/3n,···的前n项和谢谢
人气:329 ℃ 时间:2020-03-23 11:24:49
解答
sn=1/3+2/9+3/27+……+(n-1)/3(n-1)+n/3^n
3sn= 1/9 +2/27 + 3/81 … + (n-1)/ 3^n + n/3^n+1
sn-3sn= 1/3 + (1/9+1/27+1/81+……+1/3^n)-n/3^n+1
= 1/3+ (1-1/3^n-1)/1-1/3 -n/3^n+1
=1/3 +(3-1/3^n-2)/2- n/3^n+1
=11/6-(1/3^n-2)/2-n/3^n+1
sn=-11/12+(1/3^n-2)/4+(n/3^n+1)/2
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