构造一个一元二次方程:X^2 + 2X - 2 = 0
因为,a²+2a=2,b²+2b=2,a≠b
显然,a,b是方程 X^2 + 2X - 2 = 0的两个不同的根.
所以,a + b = -2,ab = -2
则 1/a + 1/b = (a + b)/(ab) = (-2)/(-2) = 1