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怎样分解x2-2xy+4y2-x-2y+1
人气:263 ℃ 时间:2020-04-20 00:33:36
解答
是不是x^2-2xy+4y^2-x-2y+1=0?
x^2-2xy+y^2+3y^2-x-2y+1=0
(x-y)^2+3(y^2-y+1/4)-(x-y)+1/4=0
(x-y)^2-(x-y)+1/4+3(y-1/2)^2=0
(x-y-1/2)^2+3(y-1/2)^2=0
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