2k/(x-1)-1/(x²-x)=(k+1)/x
2k/(x-1)-1/[x(x-1)]=(k+1)/x
2kx-1=(k+1)(x-1)
2kx-1=(k+1)x-(k+1)
(2k-k-1)x=1-(k+1)
(k-1)x=-k
x=k/(1-k)