> 数学 >
计算:1/2×4+1/4×6+1/6×8+……+1/(2n-4)(2n-2)+1/(2n-2).2n(n为正整数)
人气:349 ℃ 时间:2020-06-26 19:15:33
解答
原式
=1/2×(1/2-1/4+1/4-1/6+1/6-1/8+...+1/2n-4-1/2n-2)
=1/2×(1/2-1/2n-2)
=1/2×[1/2-1/2(n-1)]
=1/4×(1-1/n-1)
=n-2/4(n-1)
推荐
猜你喜欢
© 2024 79432.Com All Rights Reserved.
电脑版|手机版