[k(k+1)/12](3k^2+11k+10)+(k+1)(k+2) 怎么化简结果是[(k+1)(k+2)/12][3(k+1)_数学解答

[k(k+1)/12](3k^2+11k+10)+(k+1)(k+2) 怎么化简
结果是[(k+1)(k+2)/12][3(k+1)^2+11(k+1)+10] 不过我不知到详细的步骤

人气：480 ℃　时间：2020-06-27 00:09:52

解答

3k^2+11k+10=（3k+5）(k+2)[k(k+1)/12](3k^2+11k+10)+(k+1)(k+2)=[k(k+1)/12]（3k+5）(k+2)+(k+1)(k+2)=(k+1)(k+2)[k(3k+5)/12+1]=(k+1)(k+2)[k(3k+5)+12]/12=(k+1)(k+2)(3k^2+5k+1)/12