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(4a+1/a^2-1)+(2a+3/1-a^2)计算
人气:118 ℃ 时间:2020-01-30 12:54:04
解答
(4a+1/a^2-1)+2a+3/1-a^2)
=(4a+1-2a-3)/(a^2-1)
=(2a-2)/(a^2-1)
=2(a-1)/(a-1)(a+1)
=2/(a+1)
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